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(D) For equation $I$: $\sqrt{25 x^{2}} - 125 = 0$$\Rightarrow \sqrt{25 x^{2}} = 125$Squaring both sides: $25 x^{2} = 125^{2} = 15625$$\Rightarrow x^{2

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$x = y$ or the relationship cannot be established.

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(D) For equation $I$: $\sqrt{25 x^{2}} - 125 = 0$$\Rightarrow \sqrt{25 x^{2}} = 125$Squaring both sides: $25 x^{2} = 125^{2} = 15625$$\Rightarrow x^{2} = \frac{15625}{25} = 625$$	herefore x = \pm 25$For equation $II$: $\sqrt{361} y + 95 = 0$$\Rightarrow 19 y + 95 = 0$$\Rightarrow 19 y = -95$$\Rightarrow y = -\frac{95}{19} = -5$Comparing the values: If $x = 25$,then $x > y$ $(25 > -5)$. If $x = -25$,then $x Since we get two different results,the relationship between $x$ and $y$ cannot be established.

In the following questions,two equations numbered $I$ and $II$ are given. You have to solve both the equations and give the answer.
$I$: $\sqrt{25 x^{2}} - 125 = 0$
$II$: $\sqrt{361} y + 95 = 0$

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In the following questions,two equations numbered $I$ and $II$ are given. You have to solve both the equations and give the answer.$I$: $\sqrt{25 x^{2}} - 125 = 0$$II$: $\sqrt{361} y + 95 = 0$